Calling a template with several pipeline parameters


In a Go template, sometimes the way to pass the right data to the right template feels awkward to me. Calling a template with a pipeline parameter looks like calling a function with only one parameter.

Let’s say I have a site for Gophers about Gophers. It has a home page main template, and a utility template to print a list of Gophers.

Output :

*The great GopherBook*    (logged in as Dewey)

    [Most popular]  
        >> Huey
        >> Dewey
        >> Louie

    [Most active]   
        >> Huey
        >> Louie

    [Most recent]   
        >> Louie

Now I want to add a bit of context in the subtemplate : format the name “Dewey” differently inside the list because it’s the name of the currently logged user. But I can’t pass the name directly because there is only one possible “dot” argument pipeline! What can I do?

  • Obviously I can copy-paste the subtemplate code into the main template (I don’t want to because it drops all the interest of having a subtemplate).
  • Or I can juggle with some kind of global variables with accessors (I don’t want to either).
  • Or I can create a new specific struct type for each template parameter list (not great).


You could register a “dict” function in your templates that you can use to pass multiple values to a template call. The call itself would then look like that:

{{template "userlist" dict "Users" .MostPopular "Current" .CurrentUser}}

The code for the little “dict” helper, including registering it as a template func is here:

var tmpl = template.Must(template.New("").Funcs(template.FuncMap{
    "dict": func(values ...interface{}) (map[string]interface{}, error) {
        if len(values)%2 != 0 {
            return nil, errors.New("invalid dict call")
        dict := make(map[string]interface{}, len(values)/2)
        for i := 0; i < len(values); i+=2 {
            key, ok := values[i].(string)
            if !ok {
                return nil, errors.New("dict keys must be strings")
            dict[key] = values[i+1]
        return dict, nil

Answered By – tux21b

Answer Checked By – Senaida (GoLangFix Volunteer)

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