Issue
We have written one program by which we try to find an address of a constant. Is it possible to do it like that?
package main
func main() {
const k = 5
address := &k
}
It gives an error, can anyone tell how can we find the address of a constant?
Solution
In short: you can’t.
The error message says:
cannot take the address of k
There are limitations on the operand of the address operator &
. Spec: Address operators:
For an operand
x
of typeT
, the address operation&x
generates a pointer of type*T
tox
. The operand must be addressable, that is, either a variable, pointer indirection, or slice indexing operation; or a field selector of an addressable struct operand; or an array indexing operation of an addressable array. As an exception to the addressability requirement,x
may also be a (possibly parenthesized) composite literal. If the evaluation ofx
would cause a run-time panic, then the evaluation of&x
does too.
Constants are not listed as addressable, and things that are not listed in the spec as addressable (quoted above) cannot be the operand of the address operator &
(you can’t take the address of them).
It is not allowed to take the address of a constant. This is for 2 reasons:
- A constant may not have an address at all.
- And even if a constant value is stored in memory at runtime, this is to help the runtime to keep constants that: constant. If you could take the address of a constant value, you could assign the address (pointer) to a variable and you could change that (the pointed value, the value of the constant). Robert Griesemer (one of Go’s authors) wrote why it’s not allowed to take a string literal’s address: “If you could take the address of a string constant, you could call a function [that assigns to the pointed value resulting in] possibly strange effects – you certainly wouldn’t want the literal string constant to change.” (source)
If you need a pointer to a value being equal to that constant, assign it to a variable of which is addressable so you can take its address, e.g.
func main() {
const k = 5
v := k
address := &v // This is allowed
}
But know that in Go numeric constants represent values of arbitrary precision and do not overflow. When you assign the value of a constant to a variable, it may not be possible (e.g. the constant may be greater than the max value of the variable’s type you’re assigning it to – resulting in compile-time error), or it may not be the same (e.g. in case of floating point constants, it may lose precision).
Answered By – icza
Answer Checked By – Clifford M. (GoLangFix Volunteer)