How many goroutines are started by default in a Go program?

Issue

package main

import (
    //"time"
    "runtime"
    "fmt"
)

func main() {
    //time.Sleep(100 * time.Millisecond)//By adding this number of goroutine increases
fmt.Println(runtime.NumGoroutine())
}

I am trying to find out the number of goroutines in a program. My code is here. While coding this I noticed default number of goroutines is 4.

For me:

  • main is one goroutine
  • garbage collector is one goroutine

What are the others?

By adding the time.Sleep (above), the number of goroutines increases to 5. What is the reason for this?

Solution

Actually, memory management takes more than one goroutine …

The 4 initial goroutines are:

  • the main goroutine
  • the background sweeper (the phase of the garbage collection which is concurrent)
  • the scavenger (also part of the garbage collector)
  • the finalizer goroutine (exclusively running the finalizers eventually attached to objects)

Then, the time.Sleep function is called. It requires a timer. Timers are implemented in the runtime, through an additional goroutine (timerproc), which processes events stored in the timer heap. This goroutine is lazily started when the first timer is added to the heap.

Hence, you finally get 5 goroutines.

Answered By – Didier Spezia

Answer Checked By – Terry (GoLangFix Volunteer)

Leave a Reply

Your email address will not be published.