Issue
I’ve got a slice of articles in my reading list. Each Article has the attribute “FeedURL” that has the URL of the feed the article came from. When I unsubscribe from a feed, I want to be able to remove every Article that contains that Feed’s URL.
type Article struct {
FeedURL string
URL string // should be unique
// ... more data
}
func unsubscribe(articleList []Article, url string) []Article {
// how do I remove every Article from articleList that contains url?
}
func main() {
myArticleList := []Article{
Article{"http://blog.golang.org/feed.atom", "http://blog.golang.org/race-detector"},
Article{"http://planet.python.org/rss20.xml", "http://archlinux.me/dusty/2013/06/29/creating-an-application-in-kivy-part-3/"},
Article{"http://planet.python.org/rss20.xml", "http://feedproxy.google.com/~r/cubicweborg/~3/BncbP-ap0n0/2957378"},
// ... much more examples
}
myArticleList = unsubscribe(myArticleList, "http://planet.python.org/rss20.xml")
fmt.Printf("%+v", myArticleList)
}
What is the efficient way of solving this problem?
At first my code looked like this for unsubscribe:
func unsubscribe(articleList []Article, url string) []Article {
for _, article := range articleList {
if article.FeedURL == url {
articleList = append(articleList[:i], articleList[i+1:]...)
}
}
return articleList
}
But then I realized that this would change the slice and make the for loop unpredictable.
What is an efficient and pretty way to accomplish this?
Solution
To be efficient:
- Use a slice of pointers to Articles, then we will be moving pointers
to structures instead of structure values. - If the order of the Articles in the list is not important, use the
unordered algorithm; it reduces pointer movement. Otherwise, use the
ordered algorithm. In any case, minimize pointer movement. - Don’t leave dangling pointers at the end of the list. The garbage
collector will think they are still in use; it looks at the slice
capacity not the slice length. - Minimize memory allocations.
For example,
package main
import "fmt"
type Article struct {
FeedURL string
URL string // should be unique
// ... more data
}
// Remove every Article from an articleList that contains url without preserving order.
func unsubscribeUnordered(a []*Article, url string) []*Article {
for i := 0; i < len(a); i++ {
if a[i].FeedURL == url {
a[len(a)-1], a[i], a = nil, a[len(a)-1], a[:len(a)-1]
i--
}
}
return a
}
// Remove every Article from an articleList that contains url while preserving order.
func unsubscribeOrdered(a []*Article, url string) []*Article {
j := 0
for i := 0; i < len(a); i++ {
if a[i].FeedURL == url {
continue
}
if i != j {
a[j] = a[i]
}
j++
}
for k := j; k < len(a); k++ {
a[k] = nil
}
return a[:j]
}
func NewArticleList() []*Article {
return []*Article{
&Article{"http://blog.golang.org/feed.atom", "http://blog.golang.org/race-detector"},
&Article{"http://planet.python.org/rss20.xml", "http://archlinux.me/dusty/2013/06/29/creating-an-application-in-kivy-part-3/"},
&Article{"http://planet.python.org/rss20.xml", "http://feedproxy.google.com/~r/cubicweborg/~3/BncbP-ap0n0/2957378"},
// ... much more examples
}
}
func PrintArticleList(a []*Article) {
fmt.Print("[")
for _, e := range a {
fmt.Printf("%+v", *e)
}
fmt.Println("]")
}
func main() {
PrintArticleList(NewArticleList())
ao := unsubscribeOrdered(NewArticleList(), "http://planet.python.org/rss20.xml")
PrintArticleList(ao)
auo := unsubscribeUnordered(NewArticleList(), "http://planet.python.org/rss20.xml")
PrintArticleList(auo)
}
Output:
[{FeedURL:http://blog.golang.org/feed.atom URL:http://blog.golang.org/race-detector}{FeedURL:http://planet.python.org/rss20.xml URL:http://archlinux.me/dusty/2013/06/29/creating-an-application-in-kivy-part-3/}{FeedURL:http://planet.python.org/rss20.xml URL:http://feedproxy.google.com/~r/cubicweborg/~3/BncbP-ap0n0/2957378}]
[{FeedURL:http://blog.golang.org/feed.atom URL:http://blog.golang.org/race-detector}]
[{FeedURL:http://blog.golang.org/feed.atom URL:http://blog.golang.org/race-detector}]
Answered By – peterSO
Answer Checked By – Terry (GoLangFix Volunteer)