Issue
I am doing the http://tour.golang.org/. Could anyone explain this function to me lines 1,3,5 and 7, especially what ‘*’ and ‘&’ do? By mentioning them in a function declaration, what are they supposed/expected to do? A toy example:
1: func intial1(var1 int, var2 int, func1.newfunc[]) *callproperfunction {
2:
3: addition:= make ([] add1, var1)
4: for i:=1;i<var2;i++ {
5: var2 [i] = *addtother (randomstring(lengthofcurrent))
6: }
7: return &callproperfunction {var1 int, var2 int, func1.newfunc[], jackpot}
8: }
It seems that they are pointers like what we have in C++. But I cannot connect those concepts to what we have here. In other words, what ‘*’ an ‘&’ do when I use them in function declaration in Go.
I know what reference and dereference mean. I cannot understand how we can use a pointer to a function in Go? For example lines 1 and 7, what do these two lines do? The function named intial1 is declared that returns a pointer? And in line 7, we call it with arguments using the return function.
Solution
This is possibly one of the most confusing things in Go. There are basically 3 cases you need to understand:
The &
Operator
&
goes in front of a variable when you want to get that variable’s memory address.
The *
Operator
*
goes in front of a variable that holds a memory address and resolves it (it is therefore the counterpart to the &
operator). It goes and gets the thing that the pointer was pointing at, e.g. *myString
.
myString := "Hi"
fmt.Println(*&myString) // prints "Hi"
or more usefully, something like
myStructPointer = &myStruct
// ...
(*myStructPointer).someAttribute = "New Value"
*
in front of a Type
When *
is put in front of a type, e.g. *string
, it becomes part of the type declaration, so you can say “this variable holds a pointer to a string”. For example:
var str_pointer *string
So the confusing thing is that the *
really gets used for 2 separate (albeit related) things. The star can be an operator or part of a type.
Answered By – Everett
Answer Checked By – Pedro (GoLangFix Volunteer)